K. Swan vs K. Scott — prediction
Consistent bounce, medium-fast: neutral conditions, no style favored.
Warm: the ball flies a little more and fitness counts.
Dry air: the ball travels normally.
Light wind: no noticeable effect.
Surface feeds the model (surface specialization is one of its factors). Weather and altitude are context we publish for you — they do NOT move the probability.
›Ranking: #206 vs #244 (better ranked)
›Model 64% vs market 59% → the model sees it as MORE likely than the odds
The model makes K. Swan the favorite with a 64% win probability, against K. Scott's 36% — a solid favorite, though Scott keeps real chances. Converted to odds, that probability is worth about @1.55; the offered odds are around @1.70 (a 59% implied), slightly above the market, so the model is a touch more optimistic.
Several factors explain the number: #206 vs #244 (better ranked); model 64% vs market 59% → the model sees it as more likely than the odds.
Read it with perspective. Our probability is calibrated — when the model says 64%, that outcome happens roughly that percentage of the time, with ~64% out-of-sample accuracy — but being the favorite is not being the winner: roughly 36 out of every 100 times Scott wins. The model also tends to agree with the market, so the odds already capture almost all the edge: don't take it as a sure value. This is informational analysis, not a betting recommendation. 18+ · play responsibly.